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How to use test_is_pressed_true method in keyboard

Best Python code snippet using keyboard

_keyboard_tests.py

Source:_keyboard_tests.py

...182    def test_parse_hotkey_list_names(self):183        self.assertEqual(keyboard.parse_hotkey(['a', 'b', 'c']), (((1,), (2,), (3,)),))184    def test_is_pressed_none(self):185        self.assertFalse(keyboard.is_pressed('a'))186    def test_is_pressed_true(self):187        self.do(d_a)188        self.assertTrue(keyboard.is_pressed('a'))189    def test_is_pressed_true_scan_code_true(self):190        self.do(d_a)191        self.assertTrue(keyboard.is_pressed(1))192    def test_is_pressed_true_scan_code_false(self):193        self.do(d_a)194        self.assertFalse(keyboard.is_pressed(2))195    def test_is_pressed_true_scan_code_invalid(self):196        self.do(d_a)197        self.assertFalse(keyboard.is_pressed(-1))198    def test_is_pressed_false(self):199        self.do(d_a+u_a+d_b)200        self.assertFalse(keyboard.is_pressed('a'))...

test_robot_modules_button.py

Source:test_robot_modules_button.py

...17    def test_is_pressed_calls_gpio(self):18        self.btn.gpio.input = MagicMock(return_value=1)19        self.btn.is_pressed()20        self.btn.gpio.input.assert_called_with(self.pin)21    def test_is_pressed_true(self):22        self.btn.gpio.input = MagicMock(return_value=1)23        return_val = self.btn.is_pressed()24        self.assertEqual(return_val, 1)25    def test_is_pressed_false(self):26        self.btn.gpio.input = MagicMock(return_value=0)27        return_val = self.btn.is_pressed()28        self.assertEqual(return_val, 0)29    def test_continous_button_press_trigger_only_once(self):30        self.btn.gpio.input = MagicMock(return_value=1)31        vals = []32        for i in range(10):33            vals.append(self.btn.is_pressed())34        self.assertEqual(len([v for v in vals if v == 1]), 1)35    def test_is_button_hlod(self):...

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