How to use test_parse_hotkey_combinations_single_modifiers method in keyboard

Best Python code snippet using keyboard

_keyboard_tests.py

Source:_keyboard_tests.py Github

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...671 def test_parse_hotkey_combinations_single(self):672 self.assertEqual(keyboard.parse_hotkey_combinations('a'), (((1,),),))673 def test_parse_hotkey_combinations_single_modifier(self):674 self.assertEqual(keyboard.parse_hotkey_combinations('shift+a'), (((1, 5), (1, 6)),))675 def test_parse_hotkey_combinations_single_modifiers(self):676 self.assertEqual(keyboard.parse_hotkey_combinations('shift+ctrl+a'), (((1, 5, 7), (1, 6, 7)),))677 def test_parse_hotkey_combinations_multi(self):678 self.assertEqual(keyboard.parse_hotkey_combinations('a, b'), (((1,),), ((2,),)))679 def test_parse_hotkey_combinations_multi_modifier(self):680 self.assertEqual(keyboard.parse_hotkey_combinations('shift+a, b'), (((1, 5), (1, 6)), ((2,),)))681 def test_parse_hotkey_combinations_list_list(self):682 self.assertEqual(keyboard.parse_hotkey_combinations(keyboard.parse_hotkey_combinations('a, b')), keyboard.parse_hotkey_combinations('a, b'))683 def test_parse_hotkey_combinations_fail_empty(self):684 with self.assertRaises(ValueError):685 keyboard.parse_hotkey_combinations('')686 def test_add_hotkey_multistep_suppress_incomplete(self):687 keyboard.add_hotkey('a, b', trigger, suppress=True)688 self.do(du_a, [])689 self.assertEqual(keyboard._listener.blocking_hotkeys[(1,)], [])...

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