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How to use uninit_logger method in lisa

Best Python code snippet using lisa_python

logger.py

Source:logger.py

...119    stdout_logger = get_logger("stdout")120    stderr_logger = get_logger("stderr")121    sys.stdout = cast(TextIO, LogWriter(stdout_logger, logging.INFO))122    sys.stderr = cast(TextIO, LogWriter(stderr_logger, logging.ERROR))123def uninit_logger() -> None:124    # release stdout and stderr. prevent some thread errors may overrides the125    # whole log file.126    sys.stdout = _original_stdout127    sys.stderr = _original_stderr128def enable_console_timestamp() -> None:129    _console_handler.setFormatter(_format)130def add_handler(131    handler: logging.Handler,132    logger: Optional[logging.Logger] = None,133    formatter: Optional[logging.Formatter] = None,134) -> None:135    if is_unittest():136        return None137    if logger is None:...

main.py

Source:main.py

...113    finally:114        log.info(f"completed in {total_timer}")115        if file_handler:116            remove_handler(log_handler=file_handler, logger=log)117        uninit_logger()118    return exit_code119if __name__ == "__main__":120    exit_code = 0121    try:122        exit_code = main()123    except Exception as exception:124        exit_code = -1125        log = get_logger()126        try:127            log.exception(exception)128        except Exception:129            # if there is any exception in log class, they have to be caught and show130            # on console only131            traceback.print_exc()...

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