How to use test_hashable_dict method in localstack

Best Python code snippet using localstack_python

common.py

Source:common.py Github

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...126 def __key(self):127 return tuple((k,self[k]) for k in sorted(self))128 def __hash__(self):129 return 5130def test_hashable_dict():131 print('test_hashable_dict()')132 cls = HashableDict133 cls = BadHashableDict134 a = cls()135 a[0] = 0136 a[1] = 1137 b = cls()138 b[0] = 0139 b[1] = 1140 c = cls()141 c[0] = 0142 c[1] = 1143 144 d = {}145 146 d[a] = "a"147 148 print(d)149 print(d[a])150 print(d[b])151 152 a[0] = 666153 154 print(d[b])...

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test_collections.py

Source:test_collections.py Github

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...31 assert "z" not in d132 with pytest.raises(Exception) as exc:33 d1["foo"] = "bar"34 exc.match("does not support item assignment")35def test_hashable_dict():36 d1 = HashableJsonDict({"a": ["b"], "c": 1})37 d2 = HashableJsonDict({"a": "b"})38 d3 = HashableJsonDict({"c": 1, "a": ["b"]})39 d4 = HashableJsonDict({})40 assert len({d1, d2, d3}) == 241 assert {d1, d2, d3} == {d1, d2} == {d2, d3}42 assert {d1, d3} == {d3, d1}43 assert {d1, d1} == {d3, d3}44 assert {d1, d2, d3} != {d1}45 assert {d1, d2, d3} != {d2}46 assert {d1, d2, d3} != {d1, d3}47 assert {d4, d4} == {d4}48 with pytest.raises(Exception) as exc:49 d1["foo"] = "bar"...

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