How to use slowest method in stestr

Best Python code snippet using stestr_python

timing.py

Source:timing.py Github

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1# timing functions for the genetic algorithm2# Jan 20223import re4import time5import statistics6import multiprocessing7import config 8def do_match(regex, regex_input, pipe):9 time_started = time.process_time()10 regex.match(regex_input)11 time_ended = time.process_time()12 pipe.send(time_ended - time_started)13def match_time(regex, regex_input, iterations: int = 2, timeout: int = config.timeout):14 """15 Determine how long a string takes to match16 """17 times = []18 compiled_regex = re.compile(regex)19 for _ in range(iterations):20 parent_conn, child_conn = multiprocessing.Pipe()21 p = multiprocessing.Process(target=do_match, args=((compiled_regex, regex_input, child_conn, )))22 p.start()23 p.join(timeout=timeout)24 if p.is_alive():25 time_taken = timeout26 # print("TIMEOUT:", regex_input)27 p.kill()28 else:29 time_taken = parent_conn.recv()30 times.append(time_taken)31 # print("difference in time", total_time1, total_time2, abs(total_time1 - total_time2))32 return statistics.mean(times)33# def match_time(regex, regex_input):34# """35# Old version for testing 36# """37# compiled_regex = re.compile(regex)38# times = [] 39# for i in range(10):40# time_started = time.process_time()41# compiled_regex.match(regex_input)42# time_ended = time.process_time()43# times.append(time_ended-time_started)44# return statistics.mean(times)45# returns time taken per character46# no longer in use 47def average_match_time(regex, input):48 time_taken = match_time(regex, input)49 average_time = time_taken / len(input)50 return average_time51# returns slowest individual in a generation based on average matching time (per letter)52# TODO check if this is still in use 53def slowest_average_match_time(regex, generation):54 slowest_time = 055 slowest_string = ""56 for finalist in generation:57 time_taken = match_time(regex, finalist)58 if time_taken > slowest_time:59 slowest_string = finalist60 slowest_time = time_taken61 slowest_string = "".join(slowest_string)62 return slowest_string, slowest_time63# returns slowest individual in a generation based on total matching time 64def slowest_total_match_time(regex, generation):65 slowest_time = 066 slowest_string = ""67 for finalist in generation:68 time_taken = match_time(regex, finalist)69 if time_taken >= config.timeout:70 return finalist, config.timeout 71 elif time_taken > slowest_time:72 slowest_string = finalist73 slowest_time = time_taken74 return slowest_string, slowest_time75# an alternate to fittest_individual_total76# not currently in use77def slowest_individual(regex, generation):78 dict = {}79 ordered_generation = []80 for input in generation:81 if input != "":82 dict[input] = match_time(regex, input)83 sorted_inputs = sorted(dict.items(), key=lambda kv: kv[1])84 slowest_item = sorted_inputs[-1][0]85 slowest_time = sorted_inputs[-1][1]...

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slowestKey.py

Source:slowestKey.py Github

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1class Solution:2 def slowestKey(self, releaseTimes: List[int], keysPressed: str) -> str:3 slowestDuration, durationI=0,0 #durationI will contain the duration of the key pressed for the ith iteration4 slowestKey=''5 for i in range(len(keysPressed)):6 #calculate durationI7 if i==0: durationI = releaseTimes[i]8 else: durationI = releaseTimes[i] - releaseTimes[i-1]9 #only proceed if durationI is longer (greater) than the current slowest duration10 if durationI>=slowestDuration:11 if durationI==slowestDuration:12 #replace slowestKey if current key is lexicographically greater than the slowestKey13 if slowestKey<keysPressed[i]:14 slowestKey=keysPressed[i]15 slowestDuration=durationI #update slowestDuration value if slowestKEy has been replaced16 else:17 slowestKey=keysPressed[i]18 slowestDuration=durationI...

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