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How to use bsearch_index method of ArrayBSearchIndex Package

Best Test-prof_ruby code snippet using ArrayBSearchIndex.bsearch_index

array_bsearch_index.rb

Source:array_bsearch_index.rb

1# frozen_string_literal: true2module TestProf3  # Ruby 2.3 #bsearch_index method (for usage with older Rubies)4  # Straighforward and non-optimal implementation,5  # just for compatiblity6  module ArrayBSearchIndex7    refine Array do8      def bsearch_index(&block)9        el = bsearch(&block)10        index(el)11      end12    end13  end14end...

bsearch_index

Using AI Code Generation

1puts arr.bsearch_index(5)2puts arr.bsearch_index(1)3puts arr.bsearch_index(10)4puts arr.bsearch_index(11)5puts arr.bsearch_index(5)6puts arr.bsearch_index(1)7puts arr.bsearch_index(10)8puts arr.bsearch_index(11)9array.bsearch_index { |obj| block }10puts arr.bsearch_index { |x| x > 5 }11puts arr.bsearch_index { |x| x < 5 }12puts arr.bsearch_index { |x| x == 10 }13puts arr.bsearch_index { |x| x > 10 }

bsearch_index

Using AI Code Generation

1p a.bsearch_index(3)2p a.bsearch_index(1)3p a.bsearch_index(10)4p a.bsearch_index(11)5  def bsearch_index(element)6      mid = (low + high) / 27p a.bsearch_index(3)8p a.bsearch_index(1)9p a.bsearch_index(10)10p a.bsearch_index(11)11  def bsearch_index(element)12      mid = (low + high) /

bsearch_index

Using AI Code Generation

1p a.bsearch_index(3)2p a.bsearch_index(1)3p a.bsearch_index(10)4p a.bsearch_index(11)5  def bsearch_index(element)6      mid = (low + high) / 27p a.bsearch_index(3)8p a.bsearch_index(1)9p a.bsearch_index(10)10p a.bsearch_index(11)11  def bsearch_index(element)12      mid = (low + high) /

bsearch_index

Using AI Code Generation

1index = ArrayBSearchIndex.bsearch_dex(ra, element)2  def self.bsearch_index(array, element)3      mid = low + (high - low) / 24How to find an element in a rotated sorted array in O(log n) time?

bsearch_index

Using AI Code Generation

1index = a.bsearch_index(elem)2 def bsearch_index(elem)3 m = (l + u) / 24 m = (l + u) / 2

bsearch_index

Using AI Code Generation

1index = ArrayBSearchIndex.bsearch_index(array, element)2  def self.bsearch_index(array, element)3      mid = low + (high - low) / 24How to find an element in a rotated sorted array in O(log n) time?

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