How to use test_on_press_key_blocking method in keyboard

Best Python code snippet using keyboard

_keyboard_tests.py

Source:_keyboard_tests.py

...323        self.assertEqual(self.i, 3)324    def test_on_press_key_nonblocking(self):325        keyboard.on_press_key('A', lambda e: self.assertEqual(e.name, 'a') and self.assertEqual(e.event_type, KEY_DOWN))326        self.do(d_a+u_a+d_b+u_b)327    def test_on_press_key_blocking(self):328        keyboard.on_press_key('A', lambda e: e.scan_code == 1, suppress=True)329        self.do([make_event(KEY_DOWN, 'A', -1)] + d_a, d_a)330    def test_on_release_key(self):331        keyboard.on_release_key('a', lambda e: self.assertEqual(e.name, 'a') and self.assertEqual(e.event_type, KEY_UP))332        self.do(d_a+u_a)333    def test_block_key(self):334        blocked = keyboard.block_key('a')335        self.do(d_a+d_b, d_b)336        self.do([make_event(KEY_DOWN, 'A', -1)], [make_event(KEY_DOWN, 'A', -1)])337        keyboard.unblock_key(blocked)338        self.do(d_a+d_b, d_a+d_b)339    def test_block_key_ambiguous(self):340        keyboard.block_key('A')341        self.do(d_a+d_b, d_b)...

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