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How to use calculateInsertionCostOnFirstRow method of org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.CostMatrix class

Best EvoMaster code snippet using org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.CostMatrix.calculateInsertionCostOnFirstRow

Source:CostMatrix.java

...69         * 1) deletions followed by replacement70         * 2) as above, and then followed by insertions71         */72        final double[][][] matrix = new double[ROWS][COLUMNS][3];73        calculateInsertionCostOnFirstRow(graph, matrix);74        for (int i = 1; i < ROWS; i++) {75            for (int col = 0; col < COLUMNS; col++) {76                /*77                 * unless a path is explicitly updated, it will have maximum distance by default78                 */79                matrix[i][col][DEL] = Double.MAX_VALUE;80                matrix[i][col][REP] = Double.MAX_VALUE;81                matrix[i][col][INS] = Double.MAX_VALUE;82                for (GraphTransition t : graph.getIncomingTransitions(i, col)) {83                    int otherCol = graph.getColumn(t.fromState);84                    int otherRow = t.fromRow;85                    if (t.type.equals(GraphTransition.TransitionType.INSERTION)) {86                        assert otherRow == i;87                        /*88                         * if we have an insertion, only the insertion path can be continued.89                         * that's the reason why on the left side we only update for [INS].90                         * An insertion can continue any type of path (and so all types are present on the right side).91                         */92                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));93                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));94                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][INS], t.cost));95                    } else if (t.type.equals(GraphTransition.TransitionType.REPLACEMENT)) {96                        /*97                         * if we have a replacement, then we cannot continue a delete path.98                         * So, no [DEL] on the left side.99                         * A replacement can continue a delete or replace path, but not an insertion one (and so [DEL] and100                         * [REP] on right side)101                         */102                        matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));103                        matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));104                        /*105                         * from this state on, an insertion path can be followed, with same cost (ie right side) as replacement path106                         */107                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));108                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));109                    } else if (t.type.equals(GraphTransition.TransitionType.DELETION)) {110                        /*111                         * deletion can only follow a deletion path (so only [DEL] or right side).112                         * but, from this state on, any new path can be followed (so all on left side)113                         */114                        matrix[i][col][DEL] = Math.min(matrix[i][col][DEL], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));115                        matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));116                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));117                    } else if (t.type.equals(GraphTransition.TransitionType.PHANTOM)) {118                        assert t.cost == 0;119                        /*120                         * artificial transition to final/sink state, so just take same values as previous state121                         */122                        matrix[i][col][DEL] = Math.min(matrix[i][col][DEL], matrix[otherRow][otherCol][DEL]);123                        matrix[i][col][REP] = Math.min(matrix[i][col][REP], matrix[otherRow][otherCol][REP]);124                        matrix[i][col][INS] = Math.min(matrix[i][col][INS], matrix[otherRow][otherCol][INS]);125                    }126                }127            }128            /*129             * TODO: The algorithm of Myers's paper, at page 12, makes a distinction between D and E transitions.130             * Insertions of type E are done last. Not fully clear if it has an effect here: ie, recall that131             * here we do minimization (calculate distance) and not maximization (similarity)132             */133        }134        /*135         * get the minimum among the 3 different paths in the sink state136         */137        double min = Double.MAX_VALUE;138        for (double value : matrix[ROWS - 1][COLUMNS - 1]) {139            if (value < min) {140                min = value;141            }142        }143        return min;144    }145    /**146     * We cannot just do previousStateCost + transitionCost, as there might be computational overflows147     *148     * @param previousStateCost149     * @param transitionCost150     * @return151     * @throws IllegalArgumentException152     */153    private static double getSubPathCost(double previousStateCost, double transitionCost) throws IllegalArgumentException {154        if (previousStateCost < 0) {155            throw new IllegalArgumentException("previousStateCost cannot be negative: " + previousStateCost);156        }157        if (transitionCost < 0) {158            throw new IllegalArgumentException("transitionCost cannot be negative: " + transitionCost);159        }160        if (previousStateCost == Double.MAX_VALUE || transitionCost == Double.MAX_VALUE) {161            return Double.MAX_VALUE;162        }163        double sum = previousStateCost + transitionCost;164        if (sum < previousStateCost || sum < transitionCost) {165            /*166             * likely overflow167             */168            return Double.MAX_VALUE;169        }170        return sum;171    }172    /**173     * First row is special, ie very different from the others174     *175     * @param graph176     * @param matrix177     */178    private static void calculateInsertionCostOnFirstRow(RegexGraph graph, final double[][][] matrix) {179        // First row is cost of matching empty sequence on regex180        final int FIRST_ROW = 0;181        /*182         * init first starting state with 0 costs183         */184        matrix[FIRST_ROW][0][0] = 0;185        matrix[FIRST_ROW][0][1] = 0;186        matrix[FIRST_ROW][0][2] = 0;187        for (int col = 1; col < graph.getNumberOfColumns(); col++) {188            double min = Double.MAX_VALUE;189            for (GraphTransition t : graph.getIncomingTransitions(FIRST_ROW, col)) {190                /*191                 * on first row, there can be only insertions coming from the same row,192                 * apart from last node that can have a phantom transition to sink state...

calculateInsertionCostOnFirstRow

Using AI Code Generation

1public class CostMatrix {2    public static void main(String[] args) {3        int[][] matrix = new int[4][4];4        matrix[0][0] = 0;5        matrix[0][1] = 1;6        matrix[0][2] = 2;7        matrix[0][3] = 3;8        matrix[1][0] = 1;9        matrix[1][1] = 0;10        matrix[1][2] = 1;11        matrix[1][3] = 2;12        matrix[2][0] = 2;13        matrix[2][1] = 1;14        matrix[2][2] = 0;15        matrix[2][3] = 1;16        matrix[3][0] = 3;17        matrix[3][1] = 2;18        matrix[3][2] = 1;19        matrix[3][3] = 0;20        int cost = CostMatrix.calculateInsertionCostOnFirstRow(matrix);21        System.out.println("Cost of insertion of a character on the first row of the matrix is " + cost);22        cost = CostMatrix.calculateDeletionCostOnFirstColumn(matrix);23        System.out.println("Cost of deletion of a character on the first column of the matrix is " + cost);24    }25    public static int calculateInsertionCostOnFirstRow(int[][] matrix) {26        int cost = 0;27        for (int i = 0; i < matrix[0].length; i++) {28            cost += matrix[0][i];29        }30        return cost;31    }32    public static int calculateDeletionCostOnFirstColumn(int[][] matrix) {33        int cost = 0;34        for (int i = 0; i < matrix.length; i++) {

calculateInsertionCostOnFirstRow

Using AI Code Generation

1public class ExampleController {2    public int calculateInsertionCostOnFirstRow(String a, String b) {3        return CostMatrix.calculateInsertionCostOnFirstRow(a, b);4    }5}6package org.evomaster.core.problem.rest.controller;7import com.foo.ExampleControlle

calculateInsertionCostOnFirstRow

Using AI Code Generation

1public void testInsertionCostOnFirstRow() {2    String[] patterns = new String[]{"a", "b"};3    String[] strings = new String[]{"a", "b"};4    CostMatrix matrix = new CostMatrix(patterns, strings);5    int cost = matrix.calculateInsertionCostOnFirstRow();6    assertEquals(2, cost);7}8public void testDeletionCostOnFirstColumn() {9    String[] patterns = new String[]{"a", "b"};10    String[] strings = new String[]{"a", "b"};11    CostMatrix matrix = new CostMatrix(patterns, strings);12    int cost = matrix.calculateDeletionCostOnFirstColumn();13    assertEquals(2, cost);14}15public void testSubstitutionCostOnFirstRow() {16    String[] patterns = new String[]{"a", "b"};17    String[] strings = new String[]{"a", "b"};18    CostMatrix matrix = new CostMatrix(patterns, strings);19    int cost = matrix.calculateSubstitutionCostOnFirstRow();20    assertEquals(0, cost);21}22public void testSubstitutionCostOnFirstColumn() {23    String[] patterns = new String[]{"a", "b"};24    String[] strings = new String[]{"a", "b"};25    CostMatrix matrix = new CostMatrix(patterns, strings);26    int cost = matrix.calculateSubstitutionCostOnFirstColumn();27    assertEquals(0, cost);28}

calculateInsertionCostOnFirstRow

Using AI Code Generation

1CostMatrix costMatrix = new CostMatrix(1);2String regex = "a{2}";3int cost = costMatrix.calculateInsertionCostOnFirstRow(regex);4assert cost == 2;5regex = "a{3}";6cost = costMatrix.calculateInsertionCostOnFirstRow(regex);7assert cost == 3;8regex = "a{4}";9cost = costMatrix.calculateInsertionCostOnFirstRow(regex);10assert cost == 4;11regex = "a{5}";12cost = costMatrix.calculateInsertionCostOnFirstRow(regex);13assert cost == 5;14regex = "a{6}";15cost = costMatrix.calculateInsertionCostOnFirstRow(regex);16assert cost == 6;17regex = "a{7}";18cost = costMatrix.calculateInsertionCostOnFirstRow(regex);19assert cost == 7;20regex = "a{8}";21cost = costMatrix.calculateInsertionCostOnFirstRow(regex);22assert cost == 8;23regex = "a{9}";

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