# How to use fib method in Best

Best JavaScript code snippet using best

fibonacci.py

Source:fibonacci.py

`1# fibonacci.py2"""3Calculates the Fibonacci sequence using iteration, recursion, memoization,4and a simplified form of Binet's formula5NOTE 1: the iterative, recursive, memoization functions are more accurate than6the Binet's formula function because the Binet formula function uses floats7NOTE 2: the Binet's formula function is much more limited in the size of inputs8that it can handle due to the size limitations of Python floats9RESULTS: (n = 20)10fib_iterative runtime: 0.0055 ms11fib_recursive runtime: 6.5627 ms12fib_memoization runtime: 0.0107 ms13fib_binet runtime: 0.0174 ms14"""15from math import sqrt16from time import time17def time_func(func, *args, **kwargs):18 """19 Times the execution of a function with parameters20 """21 start = time()22 output = func(*args, **kwargs)23 end = time()24 if int(end - start) > 0:25 print(f"{func.__name__} runtime: {(end - start):0.4f} s")26 else:27 print(f"{func.__name__} runtime: {(end - start) * 1000:0.4f} ms")28 return output29def fib_iterative(n: int) -> list[int]:30 """31 Calculates the first n (0-indexed) Fibonacci numbers using iteration32 >>> fib_iterative(0)33 [0]34 >>> fib_iterative(1)35 [0, 1]36 >>> fib_iterative(5)37 [0, 1, 1, 2, 3, 5]38 >>> fib_iterative(10)39 [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]40 >>> fib_iterative(-1)41 Traceback (most recent call last):42 ...43 Exception: n is negative44 """45 if n < 0:46 raise Exception("n is negative")47 if n == 0:48 return [0]49 fib = [0, 1]50 for _ in range(n - 1):51 fib.append(fib[-1] + fib[-2])52 return fib53def fib_recursive(n: int) -> list[int]:54 """55 Calculates the first n (0-indexed) Fibonacci numbers using recursion56 >>> fib_iterative(0)57 [0]58 >>> fib_iterative(1)59 [0, 1]60 >>> fib_iterative(5)61 [0, 1, 1, 2, 3, 5]62 >>> fib_iterative(10)63 [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]64 >>> fib_iterative(-1)65 Traceback (most recent call last):66 ...67 Exception: n is negative68 """69 def fib_recursive_term(i: int) -> int:70 """71 Calculates the i-th (0-indexed) Fibonacci number using recursion72 """73 if i < 0:74 raise Exception("n is negative")75 if i < 2:76 return i77 return fib_recursive_term(i - 1) + fib_recursive_term(i - 2)78 if n < 0:79 raise Exception("n is negative")80 return [fib_recursive_term(i) for i in range(n + 1)]81def fib_memoization(n: int) -> list[int]:82 """83 Calculates the first n (0-indexed) Fibonacci numbers using memoization84 >>> fib_memoization(0)85 [0]86 >>> fib_memoization(1)87 [0, 1]88 >>> fib_memoization(5)89 [0, 1, 1, 2, 3, 5]90 >>> fib_memoization(10)91 [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]92 >>> fib_iterative(-1)93 Traceback (most recent call last):94 ...95 Exception: n is negative96 """97 if n < 0:98 raise Exception("n is negative")99 # Cache must be outside recursuive function100 # other it will reset every time it calls itself.101 cache: dict[int, int] = {0: 0, 1: 1, 2: 1} # Prefilled cache102 def rec_fn_memoized(num: int) -> int:103 if num in cache:104 return cache[num]105 value = rec_fn_memoized(num - 1) + rec_fn_memoized(num - 2)106 cache[num] = value107 return value108 return [rec_fn_memoized(i) for i in range(n + 1)]109def fib_binet(n: int) -> list[int]:110 """111 Calculates the first n (0-indexed) Fibonacci numbers using a simplified form112 of Binet's formula:113 https://en.m.wikipedia.org/wiki/Fibonacci_number#Computation_by_rounding114 NOTE 1: this function diverges from fib_iterative at around n = 71, likely115 due to compounding floating-point arithmetic errors116 NOTE 2: this function doesn't accept n >= 1475 because it overflows117 thereafter due to the size limitations of Python floats118 >>> fib_binet(0)119 [0]120 >>> fib_binet(1)121 [0, 1]122 >>> fib_binet(5)123 [0, 1, 1, 2, 3, 5]124 >>> fib_binet(10)125 [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55]126 >>> fib_binet(-1)127 Traceback (most recent call last):128 ...129 Exception: n is negative130 >>> fib_binet(1475)131 Traceback (most recent call last):132 ...133 Exception: n is too large134 """135 if n < 0:136 raise Exception("n is negative")137 if n >= 1475:138 raise Exception("n is too large")139 sqrt_5 = sqrt(5)140 phi = (1 + sqrt_5) / 2141 return [round(phi**i / sqrt_5) for i in range(n + 1)]142if __name__ == "__main__":143 num = 20144 time_func(fib_iterative, num)145 time_func(fib_recursive, num)146 time_func(fib_memoization, num)...`

recomb.js

Source:recomb.js

`...11 12 // define the standard factorial function to compare with13 fact = function(n){ return n <= 1 ? 1 : n * fact(n - 1); },14 // define the standard fibonacci function to compare with15 fib = function(n){ return n <= 1 ? 1 : fib(n - 1) + fib(n - 2); },16 17 // prepare the sequence of arguments for comparison18 seq = df.listcomp("i for(i = 0; i < 15; ++i)"),19 20 // build a set of results for our argument list using the standard factorial function21 factTable = df.map(seq, fact),22 // build a set of results for our argument list using the standard fibonacci function23 fibTable = df.map(seq, fib);24 25 tests.register("dojox.lang.tests.recomb", [26 function testFactLinrec1(t){27 var fact = df.linrec("<= 1", "1", "[n - 1]", "a * b[0]");28 t.assertEqual(df.map(seq, fact), factTable);29 },...`

1029.js

Source:1029.js

`1/**2 * FUNC | CALLS | VALUE |3 * fib( 0) = 0 calls = 04 * fib( 1) = 0 calls = 15 * fib( 2) = 2 calls = 16 * fib( 3) = 4 calls = 27 * fib( 4) = 8 calls = 38 * fib( 5) = 14 calls = 59 * fib( 6) = 24 calls = 810 * fib( 7) = 40 calls = 1311 * fib( 8) = 66 calls = 2112 * fib( 9) = 108 calls = 3413 * fib(10) = 176 calls = 5514 */15/**16 * Call FIB function:17 * * C(n) = [ (n - 2 > 0) ? ( C(n - 2) + 1 ) : (return 0) ) ] + [ (n - 1 > 0) ? C(n - 1) + 1 : (return 0) ]18 * * F(n) = F(n - 2) + F(n - 1)19 */20const { format } = require("util")21const { readFileSync } = require("fs")22const [numLines, ...input] = readFileSync("/dev/stdin", "utf8").split("\n")23/** @typedef {{ calls: number, value: number }} countableFibProp */24/** @type { Map<number, countableFibProp> } */25const FibonacciList = new Map([26 [0, { calls: 0, value: 0 }],27 [1, { calls: 0, value: 1 }],28 [2, { calls: 2, value: 1 }]29])30function recusiveFibonacciWithCallsCounter(nth = 0) {31 nth = Math.floor(Math.max(0, nth)) // is nth leq 0? So set nth to 032 if (FibonacciList.has(nth) === false) {33 // If not included, set it34 const fibA = recusiveFibonacciWithCallsCounter(nth - 2)35 const fibB = recusiveFibonacciWithCallsCounter(nth - 1)36 FibonacciList.set(nth, {37 calls: (fibA.calls + 1) + (fibB.calls + 1),38 value: fibA.value + fibB.value39 })40 }41 return FibonacciList.get(nth)42}43function main() {44 const output = new Array(Number.parseInt(numLines, 10))45 for (let index = 0; index < output.length; index += 1) {46 const nth = Number.parseInt(input[index])47 const { calls, value } = recusiveFibonacciWithCallsCounter(nth)48 output[index] = format("fib(%d) = %d calls = %d", nth, calls, value)49 }50 console.log(output.join("\n"))51}...`

RecursiveD5.py

Source:RecursiveD5.py

```1# Fibonacci sequence calculations23# n: 0 1 2 3 4 5 6 7 8 94# fib(n): 0 1 1 2 3 5 8 13 21 3456# A non-recursive function for calculating the nth Fibonacci number:7def fib(n):8 if n < 2:9 return n10 prev = 011 curr = 112 for i in range(2,n+1):13 new_curr = prev + curr14 prev = curr15 curr = new_curr16 return curr1718# Calculating the ratios of pairs of Fibonacci numbers -- like fib(6)/fib(5)19def CalcFibRatios(low,high):20 for i in range(low,high+1):21 print(timeit(i)/timeit(i-1))22 23# The recursive function for Fibonacci24def fib_r(n):25 if n < 2:26 return n27 return fib_r(n-1) + fib_r(n-2)2829# Timing how long it takes to calculate fib_r(n)30def timeit(n):31 import time32 start = time.time()33 fibr2(n)34 end = time.time()35 return end - start3637# Recursive Fib:38# 1 = fib(2)[2 calculation] = fib(1)[1 calculation] + fib(0)[1 calculation]39# 2 = fib(3)[3 c] = fib(2)[2 c] + fib(1)[1 c]40# 3 = fib(4)[5 c] = fib(3)[3 c] + fib(2)[2 c]41# 5 = fib(5)[8 p] = fib(4)[5 p] + fib(3)[3 c]42# So, for Recursive Fib, Fib(n) requires fib(n) calculations to occur43#44# Explicit Fib:45# 1 = fib(2)[3 c]46# 2 = fib(3)[6 c]47# 3 = fib(4)[9 c]48# 5 = fib(5)[12 c]49# So, for Explicit Fib, Fib(n) required 3n calculations5051def fibr2(n):52 return fibr2h(0, 1, 1, n)5354def fibr2h(pv, cv, i, t):55 if i == t:56 return cv57 if i - 1 == t:58 return pv59 hc = pv + cv60 hi = i + 161 hp = cv62 return fibr2h(hp, hc, hi, t) ...```

generator.js

Source:generator.js

`1function createFibGenerator() {2 let fibA = 0,3 fibB = 1,4 fibIndex = 0;5 function* generator() {6 if (fibIndex === 0) {7 fibIndex++;8 yield { value: fibA, index: 0 };9 }10 if (fibIndex === 1) {11 fibIndex++;12 yield { value: fibB, index: 1 };13 }14 while (true) {15 const result = fibA + fibB;16 fibA = fibB;17 fibB = result;18 fibIndex++;19 yield { value: result, index: fibIndex - 1 };20 }21 }22 return generator();...`

Using AI Code Generation

`1var BestFibonacci = require('./bestFibonacci.js');2var bf = new BestFibonacci();3for (var i = 0; i < 10; i++) {4 console.log(bf.fib(i));5}6var BestFibonacci = function () {7 this.memo = {};8};9BestFibonacci.prototype.fib = function (n) {10 if (n < 2) {11 return n;12 }13 if (this.memo[n]) {14 return this.memo[n];15 }16 return this.memo[n] = this.fib(n - 1) + this.fib(n - 2);17};18module.exports = BestFibonacci;19var BestFibonacci = require('./bestFibonacci.js');20for (var i = 0; i < 10; i++) {21 console.log(BestFibonacci.fib(i));22}23var BestFibonacci = function () {24 this.memo = {};25};26BestFibonacci.prototype.fib = function (n) {27 if (n < 2) {28 return n;29 }30 if (this.memo[n]) {31 return this.memo[n];32 }33 return this.memo[n] = this.fib(n - 1) + this.fib(n - 2);34};35module.exports = BestFibonacci;36var BestFibonacci = require('./bestFib`

Using AI Code Generation

`1var BestFibonacci = require('./BestFibonacci');2var bestFibonacci = new BestFibonacci();3console.log(bestFibonacci.fib(10));4function BestFibonacci() {5 this.fib = function(n) {6 if (n < 2) {7 return n;8 }9 return this.fib(n - 1) + this.fib(n - 2);10 };11}12module.exports = BestFibonacci;`

Using AI Code Generation

`1var BestFibonacci = require('./fibonacci.js');2var bf = new BestFibonacci();3var res = bf.fib(10);4console.log(res);5var BestFibonacci = function() {6 this.fib = function(n) {7 if (n === 0) {8 return 0;9 } else if (n === 1) {10 return 1;11 } else {12 return this.fib(n - 1) + this.fib(n - 2);13 }14 };15};16module.exports = BestFibonacci;17var BestFibonacci = require('./fibonacci.js');18var bf = new BestFibonacci();19var res = bf.fib(10);20console.log(res);21var Fibonacci = require('./fibonacci2.js');22var BestFibonacci = function() {23 this.fib = function(n) {24 var f = new Fibonacci();25 return f.fib(n);26 };27};28module.exports = BestFibonacci;29var BestFibonacci = require('./fibonacci.js');30var bf = new BestFibonacci();31var res = bf.fib(10);32console.log(res);33var Fibonacci = require('./fibonacci2.js');34var BestFibonacci = function() {};35BestFibonacci.prototype.fib = function(n) {`

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