How to use first_line_of_tree method in autotest

Best Python code snippet using autotest_python Github


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...534 source.close()535 result = filename, lines, excluded_lines, line_map536 self.analysis_cache[morf] = result537 return result538 def first_line_of_tree(self, tree):539 while True:540 if len(tree) == 3 and type(tree[2]) == type(1):541 return tree[2]542 tree = tree[1]543 544 def last_line_of_tree(self, tree):545 while True:546 if len(tree) == 3 and type(tree[2]) == type(1):547 return tree[2]548 tree = tree[-1]549 550 def find_docstring_pass_pair(self, tree, spots):551 for i in range(1, len(tree)):552 if self.is_string_constant(tree[i]) and self.is_pass_stmt(tree[i+1]):553 first_line = self.first_line_of_tree(tree[i])554 last_line = self.last_line_of_tree(tree[i+1])555 self.record_multiline(spots, first_line, last_line)556 557 def is_string_constant(self, tree):558 try:559 return tree[0] == symbol.stmt and tree[1][1][1][0] == symbol.expr_stmt560 except:561 return False562 563 def is_pass_stmt(self, tree):564 try:565 return tree[0] == symbol.stmt and tree[1][1][1][0] == symbol.pass_stmt566 except:567 return False568 def record_multiline(self, spots, i, j):569 for l in range(i, j+1):570 spots[l] = (i, j)571 572 def get_suite_spots(self, tree, spots):573 """ Analyze a parse tree to find suite introducers which span a number574 of lines.575 """576 for i in range(1, len(tree)):577 if type(tree[i]) == type(()):578 if tree[i][0] == symbol.suite:579 # Found a suite, look back for the colon and keyword.580 lineno_colon = lineno_word = None581 for j in range(i-1, 0, -1):582 if tree[j][0] == token.COLON:583 # Colons are never executed themselves: we want the584 # line number of the last token before the colon.585 lineno_colon = self.last_line_of_tree(tree[j-1])586 elif tree[j][0] == token.NAME:587 if tree[j][1] == 'elif':588 # Find the line number of the first non-terminal589 # after the keyword.590 t = tree[j+1]591 while t and token.ISNONTERMINAL(t[0]):592 t = t[1]593 if t:594 lineno_word = t[2]595 else:596 lineno_word = tree[j][2]597 break598 elif tree[j][0] == symbol.except_clause:599 # "except" clauses look like:600 # ('except_clause', ('NAME', 'except', lineno), ...)601 if tree[j][1][0] == token.NAME:602 lineno_word = tree[j][1][2]603 break604 if lineno_colon and lineno_word:605 # Found colon and keyword, mark all the lines606 # between the two with the two line numbers.607 self.record_multiline(spots, lineno_word, lineno_colon)608 # "pass" statements are tricky: different versions of Python609 # treat them differently, especially in the common case of a610 # function with a doc string and a single pass statement.611 self.find_docstring_pass_pair(tree[i], spots)612 613 elif tree[i][0] == symbol.simple_stmt:614 first_line = self.first_line_of_tree(tree[i])615 last_line = self.last_line_of_tree(tree[i])616 if first_line != last_line:617 self.record_multiline(spots, first_line, last_line)618 self.get_suite_spots(tree[i], spots)619 def find_executable_statements(self, text, exclude=None):620 # Find lines which match an exclusion pattern.621 excluded = {}622 suite_spots = {}623 if exclude:624 reExclude = re.compile(exclude)625 lines = text.split('\n')626 for i in range(len(lines)):627 if[i]):628 excluded[i+1] = 1...

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