How to use version_limit method in autotest

Best Python code snippet using autotest_python

kernel_versions.py

Source:kernel_versions.py

...35    for n in range(0, len(bits), 2):36        if len(bits[n]) == 1:37            bits[n] = '0' + bits[n]38    return ''.join(bits)39def version_limit(version, n):40    bits = encode_sep.split(version)41    return ''.join(bits[0:n])42def version_len(version):43    return len(encode_sep.split(version))44#45# Given a list of versions find the nearest version which is deemed46# less than or equal to the target.  Versions are in linux order47# as follows:48#49#   2.6.0 -> 2.6.1 -> 2.6.2-rc1 -> 2.6.2-rc2 -> 2.6.2 -> 2.6.3-rc150#              |        |\51#              |        | 2.6.2-rc1-mm1 -> 2.6.2-rc1-mm252#              |        \53#              |         2.6.2-rc1-ac1 -> 2.6.2-rc1-ac254#              \55#               2.6.1-mm1 -> 2.6.1-mm256#57# Note that a 2.6.1-mm1 is not a predecessor of 2.6.2-rc1-mm1.58#59def version_choose_config(version, candidates):60    # Check if we have an exact match ... if so magic61    if version in candidates:62        return version63    # Sort the search key into the list ordered by 'age'64    deco = [ (version_encode(v), i, v) for i, v in65                                    enumerate(candidates + [ version ]) ]66    deco.sort()67    versions = [ v for _, _, v in deco ]68    # Everything sorted below us is of interst.69    for n in range(len(versions) - 1, -1, -1):70        if versions[n] == version:71            break72    n -= 173    # Try ever shorter 'prefixes' 2.6.20-rc3-mm, 2.6.20-rc, 2.6. etc74    # to match against the ordered list newest to oldest.75    length = version_len(version) - 176    version = version_limit(version, length)77    while length > 1:78        for o in range(n, -1, -1):79            if version_len(versions[o]) == (length + 1) and \80                                version_limit(versions[o], length) == version:81                return versions[o]82        length -= 283        version = version_limit(version, length)84    return None85def is_released_kernel(version):86    # True if version name suggests a released kernel,87    #   not some release candidate or experimental kernel name88    #   e.g.  2.6.18-smp-200.0  includes no other text, underscores, etc89    version = version.strip('01234567890.-')90    return version in ['', 'smp', 'smpx', 'pae']91def is_release_candidate(version):92    # True if version names a released kernel or release candidate,93    #   not some experimental name containing arbitrary text94    #   e.g.  2.6.18-smp-220.0_rc3  but not  2.6.18_patched95    version = re.sub(r'[_-]rc\d+', '', version)...

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