How to use __known_block method in hypothesis

Best Python code snippet using hypothesis

data.py

Source:data.py Github

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...444 def last_block_length(self):445 return self.end(-1) - self.start(-1)446 def __len__(self):447 return len(self.endpoints)448 def __known_block(self, i):449 try:450 return self.__blocks[i]451 except (KeyError, IndexError):452 return None453 def trivial(self, i):454 """Equivalent to self.blocks[i].trivial."""455 if self.owner is not None:456 return self.start(i) in self.owner.forced_indices or not any(457 self.owner.buffer[self.start(i) : self.end(i)]458 )459 else:460 return self[i].trivial461 def _check_index(self, i):462 n = len(self)463 if i < -n or i >= n:464 raise IndexError("Index %d out of range [-%d, %d)" % (i, n, n))465 if i < 0:466 i += n467 return i468 def __getitem__(self, i):469 i = self._check_index(i)470 assert i >= 0471 result = self.__known_block(i)472 if result is not None:473 return result474 # We store the blocks as a sparse dict mapping indices to the475 # actual result, but this isn't the best representation once we476 # stop being sparse and want to use most of the blocks. Switch477 # over to a list at that point.478 if self.__sparse and len(self.__blocks) * 2 >= len(self):479 new_blocks = [None] * len(self)480 for k, v in self.__blocks.items():481 new_blocks[k] = v482 self.__sparse = False483 self.__blocks = new_blocks484 assert self.__blocks[i] is None485 start = self.start(i)486 end = self.end(i)487 # We keep track of the number of blocks that have actually been488 # instantiated so that when every block that could be instantiated489 # has been we know that the list is complete and can throw away490 # some data that we no longer need.491 self.__count += 1492 # Integrity check: We can't have allocated more blocks than we have493 # positions for blocks.494 assert self.__count <= len(self)495 result = Block(496 start=start,497 end=end,498 index=i,499 forced=start in self.owner.forced_indices,500 all_zero=not any(self.owner.buffer[start:end]),501 )502 try:503 self.__blocks[i] = result504 except IndexError:505 assert isinstance(self.__blocks, list)506 assert len(self.__blocks) < len(self)507 self.__blocks.extend([None] * (len(self) - len(self.__blocks)))508 self.__blocks[i] = result509 self.__check_completion()510 return result511 def __check_completion(self):512 """The list of blocks is complete if we have created every ``Block``513 object that we currently good and know that no more will be created.514 If this happens then we don't need to keep the reference to the515 owner around, and delete it so that there is no circular reference.516 The main benefit of this is that the gc doesn't need to run to collect517 this because normal reference counting is enough.518 """519 if self.__count == len(self) and isinstance(self.owner, ConjectureResult):520 self.owner = None521 def __iter__(self):522 for i in range(len(self)):523 yield self[i]524 def __repr__(self):525 parts = []526 for i in range(len(self)):527 b = self.__known_block(i)528 if b is None:529 parts.append("...")530 else:531 parts.append(repr(b))532 return "Block([%s])" % (", ".join(parts),)533class _Overrun:534 status = Status.OVERRUN535 def __repr__(self):536 return "Overrun"537 def as_result(self):538 return self539Overrun = _Overrun()540global_test_counter = 0541MAX_DEPTH = 100...

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