How to use normalize method of org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.RegexGraph class

Best EvoMaster code snippet using org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.RegexGraph.normalize

Source:RegexGraph.java

...56    }57    /**58     * Normalize x in [0,1]59     */60    private static double normalize(double x) {61        return x / (x + 1.0);62    }63    private static Automaton getAndCacheAutomaton(String regex) {64        /*65         * Cache it if first time we build it66         */67        if (!regexAutomatonCache.containsKey(regex)) {68            /*69             * Create an automaton representing the regex70             */71            cacheRegex(regex);72        }73        Automaton automaton = regexAutomatonCache.get(regex);74        return automaton;75    }76    private Map<Integer, Map<State, Set<GraphTransition>>> createGraph(String arg, String regex) {77        /*78         * Create a graph to calculate the distance. The algorithm is based on what discussed in:79         *80         * Mohammad Alshraideh and Leonardo Bottaci81         * Search-based software test data generation for string data using program-specific search operators82         * http://neo.lcc.uma.es/mase/attachments/085_TestDataGenerationForStringData.pdf83         *84         * and85         *86         * EUGENE W. MYERS and WEBB MILLER87         * APPROXIMATE MATCHING OF REGULAR EXPRESSIONS88         * http://www.cs.mun.ca/~harold/Courses/Old/Ling6800.W06/Diary/reg.aprox.pdf89         */90        Automaton automaton = getAndCacheAutomaton(regex);91        final int NUM_CHARS = arg.length();92        List<State> topologicalOrder = regexStateCache.get(regex);93        Map<Integer, Map<State, Set<GraphTransition>>> transitions = new HashMap<>();94        intToStateMap = new HashMap<>();95        stateToIntMap = new HashMap<>();96        int numState = 0;97        for (State currentState : topologicalOrder) {98            /*99             * Init data structure to quickly map/access state/index100             */101            stateToIntMap.put(currentState, numState);102            intToStateMap.put(numState, currentState);103            numState++;104            for (Transition t : currentState.getTransitions()) {105                State destination = t.getDest();106                ensureState(transitions, destination, NUM_CHARS);107                for (int row = 0; row <= NUM_CHARS; row++) {108                    /*109                     *  add an insertion edge from currentState in row to target state in same row110                     */111                    transitions.get(row).get(destination)112                            .add(new GraphTransition(1.0, row, currentState, GraphTransition.TransitionType.INSERTION));113                }114                for (int row = 0; row < NUM_CHARS; row++) {115                    /*116                     *  Add a replacement edge from currentState in row to t.getDest in row+1117                     *  if charAt row+1 == the parameter of this transition, this is a zero-cost edge118                     */119                    double cost = 0.0;120                    if (arg.charAt(row) < t.getMin() || arg.charAt(row) > t.getMax()) {121                        int distMin = Math.abs(arg.charAt(row) - t.getMin());122                        int distMax = Math.abs(arg.charAt(row) - t.getMax());123                        cost = normalize(Math.min(distMin, distMax));124                    }125                    /*126                     * Important: even if the cost is 0 (eg match on the arg/regex in which we replace char X with X), we CANNOT127                     * use a PHANTOM transition. Even if we do not replace anything, we still need to consider it as a replacement128                     * transition. Consider the case129                     *130                     *  "ac".matches("abc")131                     *132                     *  If we used a phantom transition to represent the alignment c/c, then it would be possible to insert 'b' in the133                     *  middle of "abc". On the other hand, if we use a replacement c/c, then inserting 'b' would not be allowed, as an134                     *  insertion cannot be followed by a replacement.135                     */136                    transitions.get(row + 1).get(destination)137                            .add(new GraphTransition(cost, row, currentState, GraphTransition.TransitionType.REPLACEMENT));...

normalize

Using AI Code Generation

1    public String normalize(String input) {2        return RegexGraph.normalize(input);3    }4    public void normalize(StringBuilder input) {5        RegexGraph.normalize(input);6    }7    public void normalize(StringBuffer input) {8        RegexGraph.normalize(input);9    }10    public void normalize(CharSequence input) {11        RegexGraph.normalize(input);12    }13    public String normalize(CharSequence input, int start, int end) {14        return RegexGraph.normalize(input, start, end);15    }16    public String normalize(String input, int start, int end) {17        return RegexGraph.normalize(input, start, end);18    }19    public String normalize(StringBuilder input, int start, int end) {20        return RegexGraph.normalize(input, start, end);21    }22    public String normalize(StringBuffer input, int start, int end) {23        return RegexGraph.normalize(input, start, end);24    }25    public String normalize(char[] input, int start, int end) {26        return RegexGraph.normalize(input, start, end);27    }28    public String normalize(char[] input) {29        return RegexGraph.normalize(input);30    }31    public String normalize(char

normalize

Using AI Code Generation

1import org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.RegexGraph;2public class RegexGraphExample {3    public static void main(String[] args) {4        String regex = "a*";5        RegexGraph graph = RegexGraph.normalize(regex);6        System.out.println(graph);7    }8}9RegexGraph{nodes=[RegexNode{from=0, to=1, type=START}, RegexNode{from=0, to=2, type=EMPTY}, RegexNode{from=1, to=2, type=EMPTY}, RegexNode{from=2, to=3, type=EMPTY}, RegexNode{from=3, to=4, type=EMPTY}, RegexNode{from=4, to=5, type=END}], edges=[RegexEdge{from=0, to=1, type=CHAR, value=a}, RegexEdge{from=0, to=2, type=EPSILON}, RegexEdge{from=1, to=2, type=EPSILON}, RegexEdge{from=2, to=3, type=EPSILON}, RegexEdge{from=3, to=4, type=EPSILON}, RegexEdge{from=4, to=5, type=EPSILON}]}10import org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.RegexGraph;11import org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.RegexGraphVisualizer;12public class RegexGraphVisualizerExample {13    public static void main(String[] args) {14        String regex = "a*";15        RegexGraph graph = RegexGraph.normalize(regex);16        RegexGraphVisualizer.visualize(graph);17    }18}

normalize

Using AI Code Generation

1import java.util.regex.Matcher;2import java.util.regex.Pattern;3public class RegexNormalize {4    public static void main(String[] args) {5        String regex = "([a-z]{3})";6        String input = "abc";7        Pattern p = Pattern.compile(regex);8        Matcher m = p.matcher(input);9        m.find();10        String normalized = RegexGraph.normalize(m.group());11        System.out.println("Normalized: " + normalized);12    }13}

normalize

Using AI Code Generation

1public class RegexNormalize {2    public static String normalize(String input){3        return RegexGraph.normalize(input);4    }5}6public class RegexNormalizeTest {7    public void testNormalize() {8        String input = "a";9        String expected = "[a]";10        String actual = RegexNormalize.normalize(input);11        Assert.assertEquals(expected, actual);12    }13}

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