Best Mockito code snippet using org.mockito.internal.util.reflection.GenericArrayReturnTypeTest.toArrayTypedDoesNotWork
Source:GenericArrayReturnTypeTest.java
...8import org.mockito.Answers;9import org.mockito.Mockito;10public class GenericArrayReturnTypeTest {11 @Test12 public void toArrayTypedDoesNotWork() throws Exception {13 GenericArrayReturnTypeTest.Container container = Mockito.mock(GenericArrayReturnTypeTest.Container.class, Answers.RETURNS_DEEP_STUBS);14 container.getInnerContainer().getTheProblem().toArray(new String[]{ });15 }16 class Container {17 private GenericArrayReturnTypeTest.InnerContainer innerContainer;18 public GenericArrayReturnTypeTest.InnerContainer getInnerContainer() {19 return innerContainer;20 }21 }22 class InnerContainer {23 private Set<String> theProblem;24 public Set<String> getTheProblem() {25 return theProblem;26 }...
toArrayTypedDoesNotWork
Using AI Code Generation
1 public void toArrayTypedDoesNotWork() {2 String[] array = new String[]{"a", "b", "c"};3 List<String> list = Arrays.asList(array);4 String[] result = GenericArrayReturnTypeTest.toArrayTypedDoesNotWork(list);5 assertThat(result).isSameAs(array);6 }7 public void toArrayTypedWorks() {8 String[] array = new String[]{"a", "b", "c"};9 List<String> list = Arrays.asList(array);10 String[] result = GenericArrayReturnTypeTest.toArrayTypedWorks(list);11 assertThat(result).isNotSameAs(array);12 }13}14The solution is to use the toArray(T[]) method, which is declared in the List interface:15T[] toArray(T[] a);
toArrayTypedDoesNotWork
Using AI Code Generation
1 public void testToArrayTypedDoesNotWork() {2 final String[] expected = { "one", "two", "three" };3 final List<String> list = Arrays.asList(expected);4 final String[] actual = GenericArrayReturnTypeTest.toArrayTypedDoesNotWork(list);5 assertArrayEquals(expected, actual);6 }7}8package org.mockito.internal.util.reflection;9import java.lang.reflect.Array;10import java.util.List;11public class GenericArrayReturnTypeTest {12 public static <T> T[] toArrayTypedWorks(final List<T> list) {13 final T[] array = (T[]) Array.newInstance(list.get(0).getClass(), list.size());14 return list.toArray(array);15 }16 public static String[] toArrayTypedDoesNotWork(final List<String> list) {17 final String[] array = (String[]) Array.newInstance(String.class, list.size());18 return list.toArray(array);19 }20}21The test testToArrayTypedDoesNotWork() fails with the following error:22java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to [Ljava.lang.String;23 at org.mockito.internal.util.reflection.GenericArrayReturnTypeTest.testToArrayTypedDoesNotWork(GenericArrayReturnTypeTest.java:14)24public static <T> T[] toArrayTypedWorks(final List<T> list) {25 final T[] array = (T[]) Array.newInstance(list.get(0).getClass(), list.size());26 return list.toArray(array);27}28public static <T> T[] toArrayTypedWorks(final List<T> list) {29 final T[] array = (T[]) Array.newInstance(list.get(0).getClass(), list.size());30 return list.toArray(array);31}
toArrayTypedDoesNotWork
Using AI Code Generation
1 public void shouldReturnEmptyArrayIfNoMethodInvocation() {2 GenericArrayReturnTypeTest obj = mock(GenericArrayReturnTypeTest.class);3 when(obj.toArrayTypedDoesNotWork()).thenReturn(new String[] { "a", "b" });4 String[] array = obj.toArrayTypedDoesNotWork();5 assertEquals(2, array.length);6 }7}
toArrayTypedDoesNotWork
Using AI Code Generation
1public class GenericArrayReturnTypeTest {2 private static class A {}3 private static class B extends A {}4 private static class C extends B {}5 private static class D extends C {}6 public void toArrayTypedWorks() {7 final A[] a = new A[]{new A(), new B(), new C(), new D()};8 final B[] b = Arrays.copyOf(a, a.length, B[].class);9 final C[] c = Arrays.copyOf(a, a.length, C[].class);10 final D[] d = Arrays.copyOf(a, a.length, D[].class);11 final A[] aa = Arrays.copyOf(b, b.length, A[].class);12 final B[] bb = Arrays.copyOf(b, b.length, B[].class);13 final C[] cc = Arrays.copyOf(b, b.length, C[].class);14 final D[] dd = Arrays.copyOf(b, b.length, D[].class);15 final A[] aaa = Arrays.copyOf(c, c.length, A[].class);16 final B[] bbb = Arrays.copyOf(c, c.length, B[].class);17 final C[] ccc = Arrays.copyOf(c, c.length, C[].class);18 final D[] ddd = Arrays.copyOf(c, c.length, D[].class);19 final A[] aaaa = Arrays.copyOf(d, d.length, A[].class);20 final B[] bbbb = Arrays.copyOf(d, d.length, B[].class);21 final C[] cccc = Arrays.copyOf(d, d.length, C[].class);22 final D[] dddd = Arrays.copyOf(d, d.length, D[].class);23 }24 public void toArrayTypedDoesNotWork() {25 final A[] a = new A[]{new A(), new B(), new C(), new D()};26 final B[] b = Arrays.copyOf(a, a.length, B[].class);27 final C[] c = Arrays.copyOf(a, a.length, C[].class);28 final D[] d = Arrays.copyOf(a, a.length, D[].class);29 final A[] aa = Arrays.copyOf(b, b.length, A[].class);30 final B[] bb = Arrays.copyOf(b, b.length, B[].class);31 final C[] cc = Arrays.copyOf(b, b.length,
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