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How to use merge method of org.testng.collections.Lists class

Best Testng code snippet using org.testng.collections.Lists.merge

Source:GuiceHelper.java

...144    for (Class<? extends Module> moduleClass : guice.modules()) {145      List<Module> modules = getGuiceModules(moduleClass);146      if (modules != null && !modules.isEmpty()) {147        result.addAll(modules);148        result = Lists.merge(result, CLASS_EQUALITY, modules);149      } else {150        Module instance = parentInjector.getInstance(moduleClass);151        result = Lists.merge(result, CLASS_EQUALITY, Collections.singletonList(instance));152        addGuiceModule(instance);153      }154    }155    Class<? extends IModuleFactory> factory = guice.moduleFactory();156    if (factory != IModuleFactory.class) {157      IModuleFactory factoryInstance = parentInjector.getInstance(factory);158      Module module = factoryInstance.createModule(context, testClass);159      if (module != null) {160        result = Lists.merge(result, CLASS_EQUALITY, Collections.singletonList(module));161      }162    }163    result = Lists.merge(result, CLASS_EQUALITY, LazyHolder.getSpiModules());164    return result;165  }166  private static final class LazyHolder {167    private static final List<Module> spiModules = loadModules();168    private static List<Module> loadModules() {169      return StreamSupport170          .stream(ServiceLoader.load(IModule.class).spliterator(), false)171          .map(IModule::getModule)172          .collect(collectingAndThen(toList(), Collections::unmodifiableList));173    }174    public static List<Module> getSpiModules() {175      return spiModules;176    }177  }...

Source:Lists.java

...32  }33  public static <K> List<K> intersection(List<K> list1, List<K> list2) {34    return list1.stream().filter(list2::contains).collect(Collectors.toList());35  }36  public static <K> List<K> merge(Collection<K> l1, Collection<K> l2) {37    List<K> result = newArrayList(l1);38    result.addAll(l2);39    return result;40  }41  /**42   * Utility method that merges two lists by applying the provided condition.43   * @param <T> - The generic type44   * @param l1 - The first list45   * @param condition - The condition that is used to determine if an element is to be added or not.46   * @param lists - The lists which are to be merged into the first list47   * @return - The merged list.48   */49  @SafeVarargs50  public static <T> List<T> merge(List<T> l1, BiPredicate<T, T> condition, List<T>... lists) {51    List<T> result = newArrayList(l1);52    Arrays.stream(lists)53        .flatMap(Collection::stream)54        .forEach(eachItem -> {55          boolean exists = result.stream().anyMatch(e -> condition.test(e, eachItem));56          if (!exists) {57            result.add(eachItem);58          }59        });60    return result;61  }62}...

Source:LinkedListMergeSortedRecursionTest.java

...31        return lst.iterator();32    }33    @Test(dataProvider = "dp")34    public void test(LinkNode<Integer> ll1, LinkNode<Integer> ll2, MyLinkedList<Integer> expected) {35       assertThat(linkedListMergeSortedRecursion.merge(ll1, ll2)).toString().equals(expected.toString());36    }37}...

Source:InsertIntervalToList.java

1package com.abn.dsalgos.algo.mergeIntervals;2import com.abn.dsalgos.utils.Interval;3import org.testng.collections.Lists;4import java.util.Arrays;5import java.util.List;6/*7Given a list of non-overlapping intervals sorted by their start time,8insert a given interval at the correct position and merge all necessary intervals to produce9a list that has only mutually exclusive intervals.10Input: Intervals=[[1,3], [5,7], [8,12]], New Interval=[4,6]11Output: [[1,3], [4,7], [8,12]]12Input: Intervals=[[1,3], [5,7], [8,12]], New Interval=[4,10]13Output: [[1,3], [4,12]]14Input: Intervals=[[2,3],[5,7]], New Interval=[1,4]15Output: [[1,4], [5,7]]16 */17//TODO: tests18public class InsertIntervalToList {19    public List<Interval> insert(List<Interval> a, Interval b) {20        if (a == null || a.isEmpty()) {21            return Arrays.asList(b);22        }23        List<Interval> merged = Lists.newLinkedList();24        int i = 0;25        while (i < a.size() && a.get(i).end < b.start) {26            merged.add(a.get(i));27            i++;28        }29        // if a and b overlaps, then a.start will be less or equal to b.end30        while (i < a.size() && a.get(i).start <= b.end) {31            b.start = Math.min(a.get(i).start, b.start);32            b.end = Math.max(a.get(i).end, b.end);33            i++;34        }35        merged.add(b);36        // add remaining ones to list37        while (i < a.size()) {38            merged.add(a.get(i++));39        }40        return merged;41    }42}...

Source:IntStreamTest.java

...13 * @since 2017å¹´06æ06æ¥ 11:3114 */15public class IntStreamTest {16  @Test17  public void mergeListArrayToMap() {18    String[] keys = {"k1", "k2", "k3"};19    List<String> values = Lists.newArrayList("v1", "v2", "v3");20    // merge List & Array to Map21    Map<String, String> map = IntStream.range(0, keys.length).boxed()22        .collect(Collectors.toMap(i -> keys[i], values::get)); // HashMap23    assertThat(map).isNotNull();24    assertThat(map.size()).isEqualTo(3);25    assertThat(map.get("k1")).isEqualTo("v1");26    assertThat(map.get("k2")).isEqualTo("v2");27    assertThat(map.get("k3")).isEqualTo("v3");28    assertThat(map.toString()).isEqualTo("{k1=v1, k2=v2, k3=v3}");29  }30  @Test(expectedExceptions = {NullPointerException.class})31  public void mergeEmptyListArrayToMap() {32    String[] keys = {"k1", "k2", "k3"};33    List<String> values = Lists.newArrayList(null, null, null);34    // merge List & Array to Map35    IntStream.range(0, keys.length).boxed()36        .collect(Collectors.toMap(i -> keys[i], values::get)); // HashMap37  }38}...

Source:MergeSortRecursionTest.java

...6import org.testng.collections.Lists;7import java.util.Iterator;8import java.util.List;9public class MergeSortRecursionTest {10    MergeSortRecursion mergeSortRecursion = new MergeSortRecursion();11    @DataProvider12    public Iterator<Object[]> dp() {13        List<Object[]> list = Lists.newLinkedList();14        list.add(new Object[] {new int[] {5, 6, 1, 2, 4, 3, 5, 8}, new int[] {1, 2, 3, 4, 5, 5, 6, 8}});15        list.add(new Object[] {new int[] {7, 1, 3}, new int[] {1, 3, 7}});16        list.add(new Object[] {new int[] {1}, new int[] {1}});17        list.add(new Object[] {new int[] {-2, 3, -5}, new int[] {-5, -2, 3}});18        return list.iterator();19    }20    @Test(dataProvider = "dp")21    public void test(int[] actual, int[] expected) {22        Assert.assertArrayEquals(mergeSortRecursion.mergeSort(actual), expected);23    }24}

Source:AlphabeticSortedMergeRecursionTest.java

...18        return list.iterator();19    }20    @Test (dataProvider = "dp")21    public void test(String str1, String str2, String expected) {22        Assert.assertEquals(alphabeticSortedMergeRecursion.mergeSortedAlphabets(str1, str2), expected);23    }24}...

Source:MergeTwoSortedArrayTest.java

1package com.abn.dsalgos.algo.merge;2import org.testng.Assert;3import org.testng.annotations.DataProvider;4import org.testng.annotations.Test;5import org.testng.collections.Lists;6import java.util.Iterator;7import java.util.List;8public class MergeTwoSortedArrayTest {9    MergeTwoSortedArrays arrays;10    @DataProvider11    public Iterator<Object[]> dp() {12        List<Object[]> lst = Lists.newLinkedList();13        lst.add(new Object[] {new int[]{1,2,3,0,0,0}, 3, new int[]{2, 5, 6}, 3, new int[]{1,2,2,3,5,6}});14        return lst.iterator();15    }16    @Test(dataProvider = "dp")17    public void test(int[] array1, int m, int[] array2, int n, int[] expected) throws Exception {18        arrays = new MergeTwoSortedArrays();19        Assert.assertEquals(arrays.merge(array1, m, array2, n), expected);20    }21}...

merge

Using AI Code Generation

1import org.testng.collections.Lists;2import java.util.List;3import java.util.ArrayList;4public class MergeList {5public static void main(String args[]) {6List<String> list1 = new ArrayList<String>();7list1.add("A");8list1.add("B");9list1.add("C");10List<String> list2 = new ArrayList<String>();11list2.add("D");12list2.add("E");13list2.add("F");14List<String> list3 = Lists.merge(list1, list2);15System.out.println("List1: " + list1);16System.out.println("List2: " + list2);17System.out.println("List3: " + list3);18}19}20import com.google.common.collect.Lists;21import java.util.List;22import java.util.ArrayList;23public class MergeList {24public static void main(String args[]) {25List<String> list1 = new ArrayList<String>();26list1.add("A");27list1.add("B");28list1.add("C");29List<String> list2 = new ArrayList<String>();30list2.add("D");31list2.add("E");32list2.add("F");33List<String> list3 = Lists.newArrayList();34list3 = Lists.newArrayList(Lists.transform(list1, Lists.stringConverter()));35list3.addAll(Lists.newArrayList(Lists.transform(list2, Lists.stringConverter())));36System.out.println("List1: " + list1);37System.out.println("List2: " + list2);38System.out.println("List3: " + list3);39}40}41import java.util.List;42import java.util.ArrayList;43import java.util.stream.Collectors;44public class MergeList {45public static void main(String args[]) {46List<String> list1 = new ArrayList<String>();47list1.add("A");48list1.add("B");49list1.add("C

merge

Using AI Code Generation

1import org.testng.collections.Lists;2public class MergeList {3  public static void main(String[] args) {4    List<String> list1 = Lists.newArrayList("A", "B", "C", "D");5    List<String> list2 = Lists.newArrayList("E", "F", "G", "H");6    List<String> mergedList = Lists.merge(list1, list2);7    System.out.println(mergedList);8  }9}

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