How to use Focus method of rod Package

Best Rod code snippet using rod.Focus

dynamic.go

Source:dynamic.go

1package dynamic2import "fmt"3/**4 * the "rod cutting" problem consists of two inputs:5 * - a list of prices for rods of integer lengths6 * - an integer length of a rod7 * the output of the problem is the maximum price8 * that can be obtained by cutting the rod into9 * integer length pieces -- and optionally the10 * places the rod need be cut in order to obtain11 * that price.12 */13type RodPrices []int14/* we can solve the problem using a divide-and-conquer15 * method by realizing that the max price can be16 * obtained by making no cuts or by starting with17 * the cut that obtains the maximum price closest18 * to one side of the rod.  then, if further cuts19 * are required, the cuts made on the other side20 * of the first cut must maximize the price of the21 * remaining length of rod, or otherwise they wouldn't22 * maximize the price of the original rod.23 *24 * this recursive version demonstrates the essential25 * reasoning described above.  it is *not* a dynamic26 * programming algorithm.27 */28func (p RodPrices) CutRodRecursive(n int) int {29	if n == 0 {30		return 031	}32	var r int33	q := p[n]34	for i := 1; i < n; i++ {35		r = p.CutRodRecursive(i)36		q = Max(q, r + p[n-i])37	}38	return q39}40func Max(x, y int) int {41	if x < y {42		return y43	}44	return x45}46/* the performance issue here and the reason this is47 * not dynamic programming is that the one call to48 * `CutRodRecursive` will cause multiple recursive49 * calls /with the same parameters/50 *51             352        /    |    \53       2     1     054    /  | \   |55   2   1  0  056 / |   |571  0   058|59*60* depicts the recursive calls necessary for an initial61* call with n=3, for instance.  it's a self-similar62* tree with a depth of 3: each level is created by63* making two copies of the current level, one with64* and one without the root node, and making all n+165* resulting root nodes the child nodes of a new root 66* node to create a tree of depth n+1.67* since the number of nodes doubles for each layer of68* depth, the number of nodes in such a tree is 2^n.69* that is, this algorithm runs in exponential time.70*71* one way to avoid the recursive calls is memoization.72* this is still not dynamic programming, although73* it is just about as performant.  it modifies the74* existing recursive algorithm to store results75* after they've been computed, avoiding traversing76* the self-similarities in the above tree.77*/78func cutRodMemoizedH(p RodPrices,79			n int, memp []int) int {80	if n == 0 {81		return 082	}83	if memo := memp[n]; memo >= 0 {84//		print("got the memo\n")85		return memo86	}87	var r int88	q := p[n]89	for i := 1; i < n; i++ {90		r = cutRodMemoizedH(p, i, memp)91		q = Max(q, r + p[n-i])92	}93	memp[n] = q94	return q95}96func (p RodPrices) CutRodMemoized(n int) int {97	memp := make([]int, n + 1)98	for idx, _ := range memp {99		memp[idx] = -1100	}101	return cutRodMemoizedH(p, n, memp)102}103/* the dynamic programming approach here is to make104 * filling in the memoization data structure, `memp`,105 * the central focus rather than viewing the data106 * structure as an add-on to a recursive approach.107 * indeed "programming" in the phrase dynamic 108 * programming refers to a data structure as in109 * the program of events at a conference, not110 * programming as in writing code:  the focus111 * is on updating a data structure based on112 * the current values in that data structure.113 */114func (p RodPrices) CutRodDP(n int) int {115	mp := make([]int, n + 1)116	mp[0] = 0117	var q, r int118	for m := 1; m <= n; m++ {119		q = p[m]120		for i := 1; i < m; i++ {121			r = mp[i]122			q = Max(q, r + p[m-i])123		}124		mp[m] = q125	}126	return mp[n]127}128/* we can additionally maintain a slice with129 * the data about the length of cuts required130 * to obtain the the maximum price131 */132func (p RodPrices) CutRodDPSol(n int) ([]int, []int) {133	mp := make([]int, n + 1)134	fc := make([]int, n + 1)135	mp[0] = 0136	var q, r, s int137	for m := 1; m <= n; m++ {138		q = p[m]139		fc[m] = m140		for i := 1; i < m; i++ {141			r = mp[i]142			s = r + p[m-i]143			if s > q {144				q = s145				fc[m] = i146			}147		}148		mp[m] = q149	}150	return mp, fc151}152/* here's maintaining solution data with the153 * memoized version154 * todo: cleanup this impl, removing excess vars, etc.155 */156func cutRodMemoSolH(p RodPrices, n int,157		memp []int, mefc [][]int) (int, []int) {158	if n == 0 {159		return 0, make([]int, 0)160	}161	if memo := memp[n]; memo >= 0 {162		return memo, mefc[n]163	}164	var r, s int165	var sol, rsol []int166	q := p[n]167	fc := n168	sol = make([]int, 0)169	for i := 1; i < n; i++ {170		r, rsol = cutRodMemoSolH(171				p, i, memp, mefc)172		s = r + p[n-i]173		if s > q {174			q = s175			fc = n-i176			sol = rsol177		}178	}179	memp[n] = q180	sol = append(sol, fc)181	mefc[n] = sol182	return q, sol183}184func (p RodPrices) CutRodMemoSol(n int) (int, []int) {185	memp := make([]int, n + 1)186	mefc := make([][]int, n + 1)187	for idx, _ := range memp {188		memp[idx] = -1189	}190	return cutRodMemoSolH(p, n, memp, mefc)191}192/* this is an alternate approach described in the193 * text, based on the notion of "density".194 * it doesn't yield correct results and is included195 * as an example of such.196 */197func (p RodPrices) GreedyCut(n int) int {198	calc_dens := func(m int) float64 {199		return float64(m)/float64(p[m])200	}201	var md, cd float64202	var mdlen int203	mdlen = n204	md = calc_dens(n)205	for m := 1; m < n; m++ {206		cd = calc_dens(m)207		if cd > md {208			mdlen = m209			md = cd210		}211	}212	if mdlen == n {213		return p[n]214	} else {215		return p[mdlen] + p.GreedyCut(n-mdlen)216	}217}218/* consider now a variation on the problem219 * wherein each cut incurs some fixed cost,220 * so the profit made from the rod is the221 * sum of the prices minus the cost of the cuts222 */223type RodPricesFC struct {224	Prices []int225	Cost int226}227func (pfc RodPricesFC) CutRodRecursive(n int) int {228	p := pfc.Prices229	c := pfc.Cost230	if n == 0 {231		return 0232	}233	var r int234	q := p[n]235	for i := 1; i < n; i++ {236		r = pfc.CutRodRecursive(i)237		q = Max(q, r + p[n-i] - c)238	}239	return q240}241func (pfc RodPricesFC) CutRodDP(n int) int {242	p := pfc.Prices243	c := pfc.Cost244	mp := make([]int, n + 1)245	mp[0] = 0246	var q, r int247	for m := 1; m <= n; m++ {248		q = p[m]249		for i := 1; i < m; i++ {250			r = mp[i]251			q = Max(q, r + p[m-i] - c)252		}253		mp[m] = q254	}255	return mp[n]256}257/**258 * the matrix-chain multiplication problem is259 * about parenthesizing matrices, not actually260 * performing multiplication:  scalar multiplication261 * is a costly computation in relation to addition262 * and all other operations involved in computing263 * the product of two matrices.264 *265 * this problem is to determine, given a sequence266 * of matrices, the order to compute pairwise267 * products in such that the pqr scalar multiplications268 * required for every two matrices of dimensions 269 * p by q and q by r is minimized over all270 * P(n) = \sum_{k=1}^{n-1} P(k)P(n-k) ~= 2^n271 * possible ways to compute the n-1 pairwise products272 * required for the (associative) product of all273 * matrices in the sequence.274 *275 * since the number of scalar multiplications is276 * dependent on the matrices dimension only, and277 * since the number of rows in each matrix must be278 * equal to the number of columns in the previous279 * matrix (if any), the input to the problem is a280 * sequence of dimensions d_0, ..., d_n281 * corresponding to a product of matrices A_1...A_n282 * such that A_i is a i - 1 by i matrix283 */284type MDims []int285/* as suggested by the above recursive calculation286 * of the number of ways to parenthesize the matrices,287 * and because the outermost parens in an optimal288 * parethesization must contain optimal 289 * parenthesizations of their subsequences in order290 * not to contradict optimality of the original291 * parethezation, a recursive calculation of the292 * number of scalar multiplications required in293 * an optimal parethezation looks like294 m[i,j] = min_{i<=k<j} {m[i,k]+m[k+1,j]+p_{i-1}p_kp_j}295 * where m[i,j] is the number of multiplications296 * required for an optimal parenthezation (one that297 * minimizes scalar multiplications) of matrices298 * A_i..A_j299 *300 * in the dynamic programming approach, we make301 * the tabular data m[i,j] central to the 302 * implementation, and focus on filling in the dynamic303 * program of m[i,j] values.  meanwhile, we keep track304 * of s[i,j], the index k=i,...,j-1 of the305 * parenthezation of A_i..A_j in order to reconstruct306 * an optimal solution rather that just compute307 * the number of multiplications in such a solution308 */309func (p MDims) ChainOrder() ([][]int, [][]int) {310	m := make([][]int, 0)311	s := make([][]int, 0)312	for i := 0; i < len(p); i++ {313		m = append(m, make([]int, len(p)))314		s = append(s, make([]int, len(p)))315	}316	for l := 2; l <= len(p) - 1; l++ {317		for i := 1; i <= len(p) - l; i++ {318			j := i + l - 1 /* at most len(d) - 1 */319			s[i][j] = i320			m[i][j] = m[i][i] + m[i+1][j] +321						p[i-1]*p[i]*p[j]322			for k := i + 1; k < j; k++ {323				mm := m[i][k] + m[k+1][j] +324						p[i-1]*p[k]*p[j]325				if mm < m[i][j] {326					m[i][j] = mm327					s[i][j] = k328				}329			}330		}331	}332	return m, s333}334/* here are some helpers for extracting an optimal335 * solution from the indices stored in s336 */337// todo: reconsider the linguistics here..338//   looking for something more like a union type,339//   which according to the faq340//  https://golang.org/doc/faq#variant_types341//   is properly implemented with an interface342type MParens struct {343	Left *MParens344	Right *MParens345	Idx int346}347func MakeMParens(s [][]int, i, j int) *MParens {348	if i == j {349			return &MParens{Idx: i}350	}351	k := s[i][j]352	return &MParens{353		Left: MakeMParens(s, i, k),354		Right: MakeMParens(s, k + 1, j),355	}356}357func (mp *MParens) String() string {358	if mp.Idx != 0 {359		return fmt.Sprintf("%d", mp.Idx)360	}361	return fmt.Sprintf("(%v%v)", mp.Left, mp.Right)362}363/* as with rod-cutting, the matrix chain multiplication364 * problem admits an inefficient recursive solution365 */366func (p MDims) chainCostAux(i, j int) int {367	if i == j {368		return 0369	}370	var mm int371	m := p.chainCostAux(i + 1, j) +372			p[i-1]*p[i]*p[j]373	for k := i; k < j; k++ {374		mm = p.chainCostAux(i, k) +375				p.chainCostAux(k+1,j) +376				p[i-1]*p[k]*p[j]377		if mm < m {378			m = mm379		}380	}381	return m382}383func (p MDims) ChainCost() int {384	return p.chainCostAux(1, len(p) - 1)385}386/* and the the recursive solution can be memoized387 * as usual388 */389func (p MDims) chainCostAuxMemo(memo [][]int, i, j int) int {390	if i == j {391		return 0392	}393	if mem := memo[i][j]; mem != 0 {394		return mem395	}396	var mm int397	m := p.chainCostAuxMemo(memo, i + 1, j) +398			p[i-1]*p[i]*p[j]399	for k := i; k < j; k++ {400		mm = p.chainCostAuxMemo(memo, i, k) +401				p.chainCostAuxMemo(memo, k+1,j) +402				p[i-1]*p[k]*p[j]403		if mm < m {404			m = mm405		}406	}407	memo[i][j] = m408	return m409}410func (p MDims) ChainCostMemo() int {411	memo := make([][]int, 0)412	for i := 0; i < len(p); i++ {413		memo = append(memo, make([]int, len(p)))414	}415	return p.chainCostAuxMemo(memo, 1, len(p) - 1)416}417/**418 * the Longest Common Sequence (LCS) problem is,419 * given two sequences X = (x_1,..., x_n) and420 * Y = (y_1, ..., y_m), to the longest sequence421 * Z = (z_1, ..., z_k) such that Z is a subsequence422 * of both X and Y.423 * we find optimal substructure in this problem424 * by considering the cases x_n == y_m and otherwise:425 * if x_n == y_m, then x_n == y_m == z_k since426 * any Z that doesn't acknowledge the last element427 * of X and Y can be made longer by including this428 * element.  otherwise, in the case x_n != y_m,429 * we cannot have z_k == x_n && z_k == y_m, so430 * the LCS of X, Y must be the LCS of either431 * X_{n-1} = (x_1,..., x_{n-1}) or Y_{n-1}.432 *433 * as with the matrix chain multiplication problem,434 * we'll fill in a program (in the sense of a table)435 * with both the value being optimized (length of436 * the LCS) as well as information about how to437 * navigate from a problem to its optimal subproblems.438 */439const (440		XA = 1441		YA = 2442		XYA = 3443)444func LCS(x, y []rune) ([][]int, [][]int) {445	m := make([][]int, 0)446	s := make([][]int, 0)447	for i := 0; i < len(x) + 1; i++ {448		m = append(m, make([]int, len(y) + 1))449		s = append(s, make([]int, len(y) + 1))450	}451	for i := 1; i < len(x) + 1; i++ {452		for j := 1; j < len(y) + 1; j++ {453			switch {454			case x[i-1] == y[j-1]:455				s[i][j] = XYA456				m[i][j] = m[i-1][j-1] + 1457			case m[i-1][j] < m[i][j-1]:458				s[i][j] = YA459				m[i][j] = m[i][j-1]460			default:461				s[i][j] = XA462				m[i][j] = m[i-1][j]463			}464		}465	}466	return m, s467}468/* reconstruct the optimal solution.469 * todo: use m, the table of lengths, to reconstruct470 */471func LCSsols(x, y []rune, s[][]int) []rune {472	rsol := make([]rune, 0)473	i := len(s) - 1474	j := len(s[0]) - 1475	for i > 0 && j > 0 {476		switch s[i][j] {477		case XYA:478			rsol = append(rsol, x[i-1])479			i--480			j--481		case XA:482			i--483		case YA:484			j--485		default:486			panic(fmt.Sprintf("unknown s %v", s[i][j]))487		}488	}489	sol := make([]rune, 0)490	for k := len(rsol) - 1; k >= 0; k-- {491		sol = append(sol, rsol[k])492	}493	return sol494}495/** todo: optimal binary search trees */...

page.go

Source:page.go

...43	for i := 0; i < 1000; i++ {44		if p.Has(selector) {45			el := p.El(selector)46			if el.MustVisible() {47				el.MustFocus()48				el.MustScrollIntoView()49				el.MustClick()50				return true51			}52		}53		time.Sleep(time.Millisecond * 100)54	}55	return false56}57func (p *PageTemplate) FocusWhenAvailable(selector string) bool {58	for i := 0; i < 1000; i++ {59		if p.Has(selector) {60			el := p.El(selector)61			el.MustFocus()62			return true63		}64		time.Sleep(time.Millisecond * 100)65	}66	return false67}68func (p *PageTemplate) MoveMouseTo(el *rod.Element) {69	shape, err := el.Shape()70	if err == nil {71		point := shape.OnePointInside()72		p.P.Mouse.MustMove(point.X, point.Y)73	} else {74		if cErr, ok := err.(*cdp.Error); ok {75			log.Println("failed to get element shape", cErr)...

bili.go

Source:bili.go

...10type BiliHandle struct {11	B *rod.Browser  //æµè§å¨å¥æ12	Page *rod.Page //é¡µé¢å¥æ13	IsLogin bool //æ¯å¦ç»å½14	FocusNumers int15}16func NewBiHandle() *BiliHandle {17	b := GetBrowser("user/bili" , false)18	page := b.MustPage("http://bilibili.com")19	login := !page.MustWaitLoad().MustHasR(".unlogin-avatar" , "ç»å½")20	return &BiliHandle{21		B:       b,22		Page:    page,23		IsLogin: login,24	}25}26//çå¾ç¨æ·ç»å½27func (b *BiliHandle) WaitLogIn(){28	if b.IsLogin {29		b.B.MustPage("http://bilibili.com").MustElement(".bili-icon_dingdao_dengchu")30	}31}32//ææ¾è§é¢33func (b *BiliHandle) Play()  {34	v := b.Page.MustElement(".video-card-reco a").MustAttribute("href")35	childPage := b.B.MustPage(fmt.Sprintf("http:%s" , *v))36	childPage.MustElement("#bilibiliPlayer").MustClick()37	childPage.MustElement(".bilibili-player-upinfo-span.restart")38	fmt.Print("vide play ending")39	childPage.Close()40	//b.MustPage()41}42//åäº«è§é¢43func (b *BiliHandle) Share ()  {44}45//ç¹èµè§é¢46func (b *BiliHandle) Like() {47	48}49type Dynamic struct {50	Time string `json:"time"`51	Content string `json:"content"`52}53// èå¤§å¥å¨çä½ 54func (b *BiliHandle)BigBrotherIsWatchingYou(id string)  {55	var  dynamicArr []Dynamic56	var dynamicArrItme Dynamic57	scpage := b.B.MustPage(fmt.Sprintf("https://space.bilibili.com/%s/dynamic" ,id))58	for {59		scpage.Reload()60		dynamicArr = nil61		scpage.MustElement(".main-content")62		arr  := scpage.MustElements(".main-content")63		for _ , v := range  arr {64			dyTime := v.MustElement(".detail-link.tc-slate").MustText()65			content := v.MustElement(".card-content").MustText()66			dynamicItem := Dynamic{67				Time:    dyTime,68				Content: content,69			}70			dynamicArr = append(dynamicArr , dynamicItem)71		}72		//ç¨åºç¬¬ä¸æ¬¡è¿è¡73		if(dynamicArrItme.Time == "" ){74			dynamicArrItme = dynamicArr[0]75			utils.WxSendMsg(string(`èå¤§å¥å·²ç»å¼å§ççä»å¦ ï¼ æåä¸æ¡å¨ææ´æ°ä¸º` + dynamicArrItme.Time))76			fmt.Println("fir")77		}78		if dynamicArrItme.Time != dynamicArr[0].Time  || dynamicArrItme.Content != dynamicArr[0].Content {79			fmt.Println("æ´æ°")80			utils.WxSendMsg(fmt.Sprintf("èå¤§å¥åç°Taçå¨æå·²ç»æ´æ°å¦ ï¼ï¼ï¼ æ¶é´ä¸º ï¼ %s , åå®¹ä¸º : %s "  , dynamicArr[0].Time ,dynamicArr[0].Content))81			dynamicArrItme = dynamicArr[0]82		}83		rand.Seed(time.Now().UnixNano())84		time.Sleep(time.Second * 3 )85	}86}87//è½¬åå¨æ88func (b *BiliHandle)Forward()  {89	90}91//è·åæå³æ³¨çåè¡¨92func (b *BiliHandle) GetFocus()  {93	var rs []string94	spacePage := b.B.MustPage("http://space.bilibili.com")95	spacePage.MustElement(".n-statistics a").MustClick()96	spacePage.MustElement(".list-item")97	for{98		arr := spacePage.MustElements(".list-item")99		for _ , v := range  arr {100			name , _ := v.MustElement(".fans-name").Text()101			rs = append(rs ,name)102		}103		if len(arr) == 20 {104			spacePage.MustElement(".be-pager-next").MustClick()105			time.Sleep(time.Second)106		}else {107			fmt.Println("ending...")108			spacePage.Close()109			break110		}111	}112	fmt.Println(rs)113	fmt.Printf( "ä¸å±å³æ³¨äººæ°ä¸º %d" , len(rs))114}115//æçç´æå³æ³¨åè¡¨116func (b *BiliHandle) GetLiveFocus (){117	type LiveItme struct {118		Name string `json:"name"`119		Status string `json:"status"`120	}121	var rsString string122	cpage := b.B.MustPage("https://link.bilibili.com/p/center/index#/user-center/follow/1")123	for{124		var liveArr []LiveItme125		cpage.Reload()126		cpage.MustElement(".favourite-card")127		arr := cpage.MustElements(".favourite-card")128		for _ , v := range arr {129			liveArr = append(liveArr , LiveItme{130				Name:   v.MustElement(".anchor-name").MustText(),...

Focus

Using AI Code Generation

1import (2func main() {3    page.MustElement("input[name=q]").MustInput("rod").MustPress(input.Enter)4    page.MustElement("a[href='/search?q=rod']").MustFocus()5    fmt.Println(page.MustScreenshot())6}7import (8func main() {9	page.MustElement("input[name=q]").MustInput("rod").MustPress(input.Enter)10	page.MustElement("a[href='/search?q=rod']").MustFocus()11	fmt.Println(page.MustScreenshot())12}13import (14func main() {15	page.MustElement("input[name=q]").MustInput("rod").MustPress(input.Enter)16	page.MustElement("a[href='/search?q=rod']").MustFocus()17	fmt.Println(page.MustHas("a[href='/search?q=rod']"))18}19import (20func main() {21	page.MustElement("input[name=q]").MustInput("rod").MustPress(input.Enter)22	page.MustElement("a[href='/search?q=rod']").MustFocus()23	fmt.Println(page.MustHas("a[href='/search?q=rod']"))24}25import (26func main() {27	page.MustElement("input[name=q]").MustInput("rod").MustPress(input.Enter)28	page.MustElement("a[href='/search?q=rod']").MustFocus()29	fmt.Println(page.Has("a[href='/search?q=rod']"))30}31import (32func main() {

Focus

Using AI Code Generation

1import (2func main() {3    page.MustElement("#hplogo").MustFocus()4    fmt.Println("Focus on Google logo")5}6import (7func main() {8    page.MustElement("#hplogo").MustFocus()9    fmt.Println("Focus on Google logo")10}11import (12func main() {13    page.MustElement("#hplogo").MustFocus()14    fmt.Println("Focus on Google logo")15}16import (17func main() {18    page.MustElement("#hplogo").MustFocus()19    fmt.Println("Focus on Google logo")20}21import (22func main() {23    page := rod.New().MustConnect().Must

Focus

Using AI Code Generation

1import (2func main() {3    browser := rod.New().Connect()4    page.Element(`input[name="q"]`).Focus()5    page.Element(`input[name="q"]`).Input("Hello World")6    page.Keyboard.Press("Enter")7    page.WaitLoad()8    title := page.MustTitle()9    fmt.Println(title)10}11import (12func main() {13    browser := rod.New().Connect()14    page.Element(`input[name="q"]`).Click()15    page.Element(`input[name="q"]`).Input("Hello World")16    page.Keyboard.Press("Enter")17    page.WaitLoad()18    title := page.MustTitle()19    fmt.Println(title)20}21import (22func main()

Focus

Using AI Code Generation

1import (2func main() {3    l := launcher.New().MustLaunch()4    defer l.Close()5    b := rod.New().ControlURL(l).MustConnect()6    input := page.MustElement("input[name=q]")7    input.MustFocus()8    input.MustInput("rod")9    input.MustPress(input.Enter)10    page.MustWaitLoad()11    page.MustScreenshot("screenshot.png")12}

Focus

Using AI Code Generation

1import (2func main() {3	browser := rod.New().Connect()4	element := page.Element("#tsf > div:nth-child(2) > div > div.RNNXgb > div > div.a4bIc > input")5	element.Focus()6	err := element.WaitVisible()7	if err != nil {8		fmt.Println(err)9	}10}112020/12/05 13:34:08 [1] [0.000s] [rod] [main.go:34] [main] rod.New: {"headless":true,"slowMotion":0,"debug":false,"defaultViewport":null,"executablePath":"","timeout":0,"monitor":0,"extra":null,"devtools":false,"trace":false,"logger":null,"launcher":null,"controlURL":"","controlTimeout":0,"controlBrowser":null,"controlPage":null}122020/12/05 13:34:08 [1] [0.000s] [rod] [main.go:34] [main] rod.New: {"headless":true,"slowMotion":0,"debug":false,"defaultViewport":null,"executablePath":"","timeout":0,"monitor":0,"extra":null,"devtools":false,"trace":false,"logger":null,"launcher":null,"controlURL":"","controlTimeout":0,"controlBrowser":null,"controlPage":null}132020/12/05 13:34:08 [1] [0.000s] [rod] [main.go:34] [main] rod.New: {"headless":true,"slowMotion":0,"debug":false,"defaultViewport":null,"executablePath":"","timeout":0,"monitor":0,"extra":null,"devtools":false,"trace":false,"logger":null,"launcher":null,"controlURL":"","controlTimeout":0,"controlBrowser":null,"controlPage":null}142020/12/05 13:34:08 [1] [0.000s] [rod] [main.go:34] [main] rod.New: {"headless

Focus

Using AI Code Generation

1import "fmt"2type Rod struct {3}4func (r Rod) Focus() {5fmt.Println("Focus method of Rod class")6}7func main() {8r.Focus()9}10import "fmt"11type Rod struct {12}13func (r *Rod) Focus() {14fmt.Println("Focus method of Rod class")15}16func main() {17r.Focus()18fmt.Println("Length of rod is:", r.length)19}20import "fmt"21type Rod struct {22}23func (r *Rod) Focus() {24fmt.Println("Focus method of Rod class")25}26func main() {27r.Focus()28fmt.Println("Length of rod is:", r.length)29}30import "fmt"31type Rod struct {32}33func (r Rod) Focus

Focus

Using AI Code Generation

1import (2func main() {3	l := launcher.New().Headless(false)4	browser := rod.New().ControlURL(l).MustConnect()5	defer browser.MustClose()6	page.MustWaitLoad()7	searchBar := page.MustElement("input[name=q]")8	searchBar.MustFocus()9	searchBar.MustInput("Rod")10	page.MustElement("input[name=btnK]").MustClick()11	page.MustWaitLoad()12	title := page.MustTitle()13	fmt.Println(title)14}

Focus

Using AI Code Generation

1{2    {3        static void Main(string[] args)4        {5            Rod myRod = new Rod();6            myRod.Focus();7        }8    }9}10{11    {12        static void Main(string[] args)13        {14            Rod myRod = new Rod();15            myRod.Focus();16        }17    }18}19{20    {21        static void Main(string[] args)22        {23            Rod myRod = new Rod();24            myRod.Focus();25        }26    }27}28{29    {30        static void Main(string[] args)31        {32            Rod myRod = new Rod();33            myRod.Focus();34        }35    }36}37{38    {

Automation Testing Tutorials

Learn to execute automation testing from scratch with LambdaTest Learning Hub. Right from setting up the prerequisites to run your first automation test, to following best practices and diving deeper into advanced test scenarios. LambdaTest Learning Hubs compile a list of step-by-step guides to help you be proficient with different test automation frameworks i.e. Selenium, Cypress, TestNG etc.